PCI: dwc: Small computation improvement

Replace a division by 2 operation for a right shift rotation of 1 bit.

Probably any recent and decent compiler does this kind of substitution
in order to improve code performance. Nevertheless it's a coding good
practice whenever there is a division / multiplication by multiple of 2
to replace it by the equivalent operation in this case, the shift
rotation.

Signed-off-by: Gustavo Pimentel <gustavo.pimentel@synopsys.com>
Signed-off-by: Lorenzo Pieralisi <lorenzo.pieralisi@arm.com>
Acked-by: Jingoo Han <jingoohan1@gmail.com>
Acked-by: Joao Pinto <jpinto@synopsys.com>
This commit is contained in:
Gustavo Pimentel 2018-05-14 16:09:49 +01:00 committed by Lorenzo Pieralisi
parent b4a8a51caf
commit 6995de2168

View File

@ -332,8 +332,8 @@ int dw_pcie_host_init(struct pcie_port *pp)
cfg_res = platform_get_resource_byname(pdev, IORESOURCE_MEM, "config");
if (cfg_res) {
pp->cfg0_size = resource_size(cfg_res) / 2;
pp->cfg1_size = resource_size(cfg_res) / 2;
pp->cfg0_size = resource_size(cfg_res) >> 1;
pp->cfg1_size = resource_size(cfg_res) >> 1;
pp->cfg0_base = cfg_res->start;
pp->cfg1_base = cfg_res->start + pp->cfg0_size;
} else if (!pp->va_cfg0_base) {
@ -377,8 +377,8 @@ int dw_pcie_host_init(struct pcie_port *pp)
break;
case 0:
pp->cfg = win->res;
pp->cfg0_size = resource_size(pp->cfg) / 2;
pp->cfg1_size = resource_size(pp->cfg) / 2;
pp->cfg0_size = resource_size(pp->cfg) >> 1;
pp->cfg1_size = resource_size(pp->cfg) >> 1;
pp->cfg0_base = pp->cfg->start;
pp->cfg1_base = pp->cfg->start + pp->cfg0_size;
break;