forked from luck/tmp_suning_uos_patched
blk-mq: put the driver tag of nxt rq before first one is requeued
When freeing the driver tag of the next rq with an I/O scheduler configured, we get the first entry of the list. However, this can race with requeue of a request, and we end up getting the wrong request from the head of the list. Free the driver tag of next rq before the failed one is requeued in the failure branch of queue_rq callback. Signed-off-by: Jianchao Wang <jianchao.w.wang@oracle.com> Signed-off-by: Jens Axboe <axboe@kernel.dk>
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@ -1094,7 +1094,7 @@ bool blk_mq_dispatch_rq_list(struct request_queue *q, struct list_head *list,
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bool got_budget)
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{
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struct blk_mq_hw_ctx *hctx;
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struct request *rq;
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struct request *rq, *nxt;
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int errors, queued;
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if (list_empty(list))
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@ -1151,14 +1151,20 @@ bool blk_mq_dispatch_rq_list(struct request_queue *q, struct list_head *list,
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if (list_empty(list))
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bd.last = true;
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else {
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struct request *nxt;
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nxt = list_first_entry(list, struct request, queuelist);
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bd.last = !blk_mq_get_driver_tag(nxt, NULL, false);
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}
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ret = q->mq_ops->queue_rq(hctx, &bd);
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if (ret == BLK_STS_RESOURCE) {
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/*
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* If an I/O scheduler has been configured and we got a
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* driver tag for the next request already, free it again.
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*/
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if (!list_empty(list)) {
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nxt = list_first_entry(list, struct request, queuelist);
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blk_mq_put_driver_tag(nxt);
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}
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blk_mq_put_driver_tag_hctx(hctx, rq);
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list_add(&rq->queuelist, list);
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__blk_mq_requeue_request(rq);
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@ -1181,13 +1187,6 @@ bool blk_mq_dispatch_rq_list(struct request_queue *q, struct list_head *list,
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* that is where we will continue on next queue run.
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*/
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if (!list_empty(list)) {
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/*
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* If an I/O scheduler has been configured and we got a driver
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* tag for the next request already, free it again.
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*/
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rq = list_first_entry(list, struct request, queuelist);
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blk_mq_put_driver_tag(rq);
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spin_lock(&hctx->lock);
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list_splice_init(list, &hctx->dispatch);
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spin_unlock(&hctx->lock);
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