forked from luck/tmp_suning_uos_patched
audit: Use struct_size() helper in alloc_chunk
One of the more common cases of allocation size calculations is finding the size of a structure that has a zero-sized array at the end, along with memory for some number of elements for that array. For example: struct audit_chunk { ... struct node { struct list_head list; struct audit_tree *owner; unsigned index; /* index; upper bit indicates 'will prune' */ } owners[]; }; Make use of the struct_size() helper instead of an open-coded version in order to avoid any potential type mistakes. So, replace the following form: offsetof(struct audit_chunk, owners) + count * sizeof(struct node); with: struct_size(chunk, owners, count) This code was detected with the help of Coccinelle. Signed-off-by: Gustavo A. R. Silva <gustavoars@kernel.org> Signed-off-by: Paul Moore <paul@paul-moore.com>
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@ -188,11 +188,9 @@ static struct fsnotify_mark *alloc_mark(void)
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static struct audit_chunk *alloc_chunk(int count)
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{
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struct audit_chunk *chunk;
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size_t size;
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int i;
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size = offsetof(struct audit_chunk, owners) + count * sizeof(struct node);
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chunk = kzalloc(size, GFP_KERNEL);
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chunk = kzalloc(struct_size(chunk, owners, count), GFP_KERNEL);
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if (!chunk)
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return NULL;
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